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8b^2=224+24b
We move all terms to the left:
8b^2-(224+24b)=0
We add all the numbers together, and all the variables
8b^2-(24b+224)=0
We get rid of parentheses
8b^2-24b-224=0
a = 8; b = -24; c = -224;
Δ = b2-4ac
Δ = -242-4·8·(-224)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-88}{2*8}=\frac{-64}{16} =-4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+88}{2*8}=\frac{112}{16} =7 $
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